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The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I (d B) = 10 log left-bracket StartFraction I Over I Subscript 0 Baseline EndFraction Right-bracket, where I is the intensity of a given sound and I0 is the threshold of hearing intensity. What is the intensity, in decibels, [I(dB)], when I = 10 Superscript 32 Baseline (I Subscript 0)?

Answer :

abidemiokin

Answer:

The intensity in decibel is 320 decibel

Step-by-step explanation:

Given the intensity, or loudness, of a sound  measured in decibels (dB), according to the equation [tex]I (dB)= 10log(\frac{I}{Io} )[/tex] where;

I is the intensity of a given sound and

[tex]Io[/tex] is the threshold of hearing intensity

To get I(dB) when [tex]I=10^{32} Io[/tex]

We will substitute the value of I = [tex]I=10^{32} Io[/tex] into the equation above to have;

[tex]I (dB)= 10log(\frac{10^{32}Io }{Io} )\\I(dB)=10log10^{32}\\ I(dB)=32*10log10\\[/tex]

Since log10 = 1;

[tex]I(dB)=32*10(1)\\I(dB)=320[/tex]

The intensity in decibel is 320 decibel

Answer:

Its D or 80

Step-by-step explanation:

I=10^8 (I subscript 0) can be written as I/I subscript 0, and you can plug that right into the log to get 80.

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