Given triangle SZU, UJ=9,VJ=3 , what’s the length of JY?
A. 4.5
B. 3
C. 18
D. 6
Please help me with this

[tex]answer = 4.5 \\ solution \\ uj = 9 \\ vj = 3 \\ \frac{uj}{jy} = \frac{2}{1} \\ or \: \frac{9}{jy} = \frac{2}{1} \\ or \: 2 \times jy = 9 \times 1 \\ or \: 2 \: jy = 9 \\ or \: jy = \frac{9}{2} \\ jy = 4.5 \\ hope \: it \: helps[/tex]
The length of JY is 4.5 units.
Centroid of a Triangle is defined as three medians of a triangle intersect to produce the centroid of the triangle. It is one of a triangle's four points of concurrent.
Given data as :
In triangle ΔSZU,
Length of UJ=9,
Length of VJ=3,
To determine the length of JY
Since, UJ and JY are medians and J centroid in triangle ΔSZU
The medians are divided into a 2:1 ratio by the centroid.
So, UJ/JY = 2/1
⇒ 9/JY = 2/1
⇒ 2JY = 9
⇒ JY = 9/2
⇒ JY = 4.5 units
Hence, the length of JY is 4.5 units.
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