Answer :
Answer:
[tex]\lambda=4.81\times 10^{-8}\ m[/tex]
Explanation:
We have,
The surface temperature of the star is 60,000 K
It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :
[tex]\lambda T=2.89\times 10^{-3}[/tex]
Here,
[tex]\lambda[/tex] = wavelength
[tex]\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m[/tex]
So, the wavelength of the star is [tex]4.81\times 10^{-8}\ m[/tex].