Answer :

unicorn3125

Answer:

            10,450

Step-by-step explanation:

21-13=8   and   29-21=8

So this is aritmetic series where a₁ = 13, and r = 8

Sum of the first n terms:  

[tex]S_n=\dfrac{a_1+a_n}{2}\cdot n=\dfrac{a_1+a_1+(n-1)r}{2}\cdot n=\dfrac{2a_1+(n-1)r}{2}\cdot n\\\\\\S_{50}=\dfrac{2\cdot13+(50-1)\cdot8}{2}\cdot50=(13+49\cdot4)\cdot 50=10,450[/tex]

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