Answer:
The number of turns present in the loop are 625 turns.
Explanation:
Given;
current on the rectangular loop, I = 6A
Dimension of the rectangular loop, L x B = 0.04 m × 0.08 m
Magnetic moment of the loop, Pm = 12 Am²
Area of the rectangular loop, A = L x B = 0.04 m × 0.08 m = 0.0032 m²
The magnetic moment of plane carrying coil/loop is given as;
Pm = NIA
Where;
N is the number of turns
A is the area of the loop
I is the current on the loop
[tex]N = \frac{P_m}{IA} \\\\N = \frac{12}{6*0.0032}\\\\N = 625 \ turns[/tex]
Therefore, the number of turns present in the loop are 625 turns.
