Steps to solve:
4x^2 - 16 = 0
~Add 16 to both sides
4x^2 = 16
~Divide 4 to both sides
x^2 = 4
~Take square root of both sides
x = ±2
Best of Luck!
[tex]\framebox{\parbox[t][1.0cm]{4.50cm}{\addvspace{0.2cm} \centering $ \;\; \,x=-2\\ \;\; \;\; $ } }\\[/tex]
[tex]\framebox{\parbox[t][1.0cm]{4.50cm}{\addvspace{0.2cm} \centering $ \;\; \, x=2\;\; \;\; $ } }\\[/tex]
Step-by-step explanation:
[tex]4x^2-16=0[/tex]
Let's factor this equation.
[tex]4x^2-16=0[/tex]
We will need to factor out the left side of the equation.
[tex]4(x+2)(x-2)=0[/tex]
The set factors must be equal to zero.
[tex]x+2=0 \\or\\x-2=0[/tex]
So now we have two answers.
[tex]x=-2\\or\\x=2[/tex]
Hope this helps!
