Answer :

saairgoodesherrod60
$\frac{9-r^2}{r^2-2r-3}\cdot\frac{4-4r^2}{r^2+4r+3}=\frac {4\left(r-1\right)}{r+1}$9− r 2 r 2−2 r −3 ·4−4 r 2 r 2+4 r +3 =4( r −1) r +1. Steps.

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