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Answer:
t = 300
Step-by-step explanation:
[tex]\huge P = 10(2)^{ \frac{t}{60} } \\ \\ \huge 320 = 10(2)^{ \frac{t}{60} }\\(plug \: P= 320) \\ \\ \huge \frac{320}{10} = (2)^{ \frac{t}{60} } \\ \\ \huge 32 = (2)^{ \frac{t}{60} } \\ \\\huge {2}^{5} = (2)^{ \frac{t}{60} } \\ \\\huge 5 = \frac{t}{60} \\(bases\: are \:same, \:so \:exponents \: would \:be\: \\equal) \\ \huge 5 \times 60 = t \\ \\300 = t \\ \\\huge\purple {\boxed {t = 300}} [/tex]
Answer:
Step-by-step explanation:
Given, the function:
To find
Solution
Substituting P with its value of 320 in the given equation: