Answer :
Let n be the required number of 33 ohm resistors.
[tex]n\times(\frac{1}{33})=\frac{1}{5.}[/tex]
[tex]n=\frac{33}{5.5}=6[/tex]
The required number of 33 ohm resistors in parallel is 6 resistors.
[tex]n\times(\frac{1}{33})=\frac{1}{5.}[/tex]
[tex]n=\frac{33}{5.5}=6[/tex]
The required number of 33 ohm resistors in parallel is 6 resistors.
Answer:
6 resistors.
Step-by-step explanation:
Common resistance of carbon resistors has been given as 3 Ω
When resistors added in parallel connection total resistance is given by the expression
[tex]\frac{1}{R}[/tex] = [tex]\frac{1}{R_1}[/tex] + [tex]\frac{1}{R_2}[/tex]...........[tex]\frac{1}{R_n}[/tex]
If n resistors have been added then [tex]\frac{1}{R}[/tex] = [tex]\frac{n}{r}[/tex]
here r = 3Ω and R = (0.5)Ω
[tex]\frac{n}{3}[/tex]= [tex]\frac{1}{0.5}[/tex]
n = [tex]\frac{3}{0.5}[/tex] = 6 resistors.