Answer :
the line is parallel so the slope is the same. So the slope = 2
Using a point-slope equation we have
y-y1 = 2(x-x1)
plug in the points
y-1 = 2(x-(-2))
=> y = 2x + 4 - 1
=> y = 2x +3
Using a point-slope equation we have
y-y1 = 2(x-x1)
plug in the points
y-1 = 2(x-(-2))
=> y = 2x + 4 - 1
=> y = 2x +3