Answer :

Yipes
[tex]d=3,7\frac{kg}{m^{3}}=3,7\frac{1000g}{1000000mL}=0,0037\frac{g}{mL}\\ m=2,5g\\\\ d=\frac{m}{V} \ \ |*V\\ dV=m \ \ |:d\\ V=\frac{m}{d}=\frac{2,5g}{0,0037\frac{g}{mL}}\approx 675,68mL[/tex]
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Answer:

Burger

Explanation:

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