If f(x)=2x(With an exponent of 2) -3, find f(-2)

[tex]f\left(x\right)=2x^2-3f ( x ) = 2 x 2 − 3 find f\left(-2\right)f ( − 2 ).[/tex]

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Today at 9:14 PM
Mathematics

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If f(x)=2x(With an exponent of 2) -3, find f(-2)

[tex]f\left(x\right)=2x^2-3f ( x ) = 2 x 2 − 3 find f\left(-2\right)f ( − 2 ).[/tex]

Answer :

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sqdancefan sqdancefan · Answer 1 · 2025-03-29T21:19:56-04:00

sqdancefan sqdancefan

Today at 9:19 PM

Answer:

5

Step-by-step explanation:

Put -2 where x is and do the arithmetic.

f(x) = 2x² -3

f(-2) = 2(-2)² -3 = 2(-2)(-2) -3 = 8 -3

f(-2) = 5

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Wolfyy Wolfyy · Answer 2 · 2025-03-29T21:19:53-04:00

Wolfyy Wolfyy

Today at 9:19 PM

Answer:

f(-2) = 5

Step-by-step explanation:

We just need to substitute x with -2 and simplify.

f(x) = 2x² - 3

f(-2) = 2(-2)² - 3

f(-2) = 2(4) - 3

f(-2) = 8 - 3

f(-2) = 5

Best of Luck!

Answer Link

If f(x)=2x(With an exponent of 2) -3, find f(-2) [tex]f\left(x\right)=2x^2-3f ( x ) = 2 x 2 − 3 find f\left(-2\right)f ( − 2 ).[/tex]

Answer :

Other Questions

If f(x)=2x(With an exponent of 2) -3, find f(-2)

[tex]f\left(x\right)=2x^2-3f ( x ) = 2 x 2 − 3 find f\left(-2\right)f ( − 2 ).[/tex]