if pes represents the potential energy stored in a spring in kg•m^2/s^2 and x represents the change in the springs length from its equilibrium position im m what is the unit for the spring constant k in the formula PEs=1/2kx^2
Unit for x - the change in the spring length: x = [ m ] PE s = 1/2 k x² [ kg m² / s² ] = 1/2 k * [ m² ] /: m² k = [ kg / s² ] Answer: The unit for spring constant k is kg/ s²
