Answer :
Step-by-step explanation:
Let the dimension of the box be x, y and z.
Volume of the box V = xyz
Since the box is a rectangular box, the base will be a square of equal length.
V = x²h where h is the height of the box
If the sum of the length, width, and height equals 180, then x+x+h = 180
2x+h = 180
h = 180-2x
Substitute h = 180-2x into the volume of the box
V = x²(180-2x)
V = 180x²-2x³
The box has its maximum volume when [tex]\frac{dV}{dx} = 0[/tex]
[tex]\frac{dV}{dx} = 360x-6x^{2}[/tex]
[tex]360x-6x^{2} = 0\\360x = 6x^2\\360 = 6x\\6x = 360\\x = \frac{360}{6}\\ x = 60[/tex]
Since 2x+h = 180
Substitute x = 60 into the equation ang get the height h
2(60)+h = 180
120+h = 180
h = 180-120
h = 60
Hence the dimension of the rectangular box is 60 by 60 by 60
The dimensions of the rectangular box of maximum volume are;
Length = 60
Length = 60Width = 60
Length = 60Width = 60Height = 60
Let the dimensions of the rectangular box be;
Length = x
Width = y
Height = h
Volume of a rectangular box is given by;
V = length × width × height
Thus;
Volume of this box in question is;
V = xyz
The box is called a rectangular box because it's sides are rectangular in shape but it's base will be square in shape.
Thus;
width = x and so;
V = x²h
We are given the sum of the length, width, and height of the rectangular box to be equal to 180.
Thus; x + x + h = 180
2x + h = 180
h = 180-2x
Put 180 - 2x for h in the equation for volume;
V = x²(180 - 2x)
V = 180x² - 2x³
The maximum volume will occur at the dimensions when dV/dx = 0. Thus;
dV/dx = 360x - 6x²
At dV/dx = 0, we have;
360x - 6x² = 0
6x² = 360x
x = 60
Recall that; h = 180 - 2x, thus;
h = 180 - 2(60)
h = 60
Read more at;https://brainly.com/question/19053087