Answer :
Answer:
1.06 m
Explanation:
We have 2.35 moles of pure urea in 1000 ml solution
Mass of the solution = 1000 × 2.35 = 2350 g
Mass of pure urea = 2.35 ×60 = 141 g
Mass of water= 2350 - 141 = 2209 g
Molality = 2.35 / 2209 × 1000 =1.06 m
Answer:
1.06 m
Explanation:
We have 2.35 moles of pure urea in 1000 ml solution
Mass of the solution = 1000 × 2.35 = 2350 g
Mass of pure urea = 2.35 ×60 = 141 g
Mass of water= 2350 - 141 = 2209 g
Molality = 2.35 / 2209 × 1000 =1.06 m