Answer :
Answer:
(1). 1/2 Cl2 + e^- --------++> Cl^-.
(2). Cd(s) ---------------> Cd^2+(aq) + 2e^-.
(3). Cl2(g) + Cd(s) ---------------> Cd^2+(aq) + 2Cl^-(aq).
Explanation:
There are different kinds or types of chemical reactions some of them are combination reaction, decomposition reaction, double decomposition reaction, elimination reaction, reduction- oxidation reaction (REDOX) and many more.
So, this question asked us about the reduction- oxidation(REDOX) reaction. This kind of reaction deals with changes in electron or oxidation rates.
For the reduction part, we have;
1/2 Cl2(g) + e^- --------++> Cl^-(aq).
For the oxidation part, we have;
Cd(s) ---------------> Cd^2+(aq) + 2e^-.
This, the overall reaction gives:
Cl2(g) + Cd(s) ---------------> Cd^2+(aq) + 2Cl^-(aq).
The net reaction is; Cd(s) + Cl2(g) ----> Cd^2+(aq) + 2Cl^-(aq).
What is a half reaction?
The term half reaction refers to the equation that would involve either oxidation or reduction.
The oxidation half equation is; Cd(s) ---->Cd^2+(aq) + 2e while the reduction half equation is; Cl2(g) + 2e ----->2Cl^-(aq). The net reaction is; Cd(s) + Cl2(g) ----> Cd^2+(aq) + 2Cl^-(aq).
Learn more about half reaction:https://brainly.com/question/10668307
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Missing parts:
Complete question: Consider the battery. Cd(s)/CdCl(aq) || CHaq) Cl2(1) C(s) (1) Write the reduction half-reaction occurring at the C(s) electrode. Include physical states. (Note the C(s) serves as a conductor). (2) Write the oxidation half reaction. (3) Write the net cell reaction.