So if 5x+1=-14 and you have to find the value of 3x+1, then you have to find x in the first equation, so:
5x+1=-14
-1 -1
Subtract one on both sides and you will have:
5x=-15
Now divide by five to get x by itself
5x/5=-15/5
x=-3
Now plug that in to 3x+1
3x+1=
3(-3)+1=
-9+1=
-8
Now for the next question 4(s+2)-2=22, you are trying to find the value of s to find the value of 3s+2. So you want to distribute the 4 to the s and to the two:
So 4(s) + 4(2) - 2 = 22
You will get:
4s+8-2=22
Simply:
4s+6=22
Subtract six from both sides of the equation
4s=16
Divide four on both sides to get s by itself:
4s/4 = 16/4
s=4
Plug that in to the second equation:
3s+2=
3(4)+2=
12+2=
14
Hope this helps!
