Answer :
The number of potential passwords that can be created in this scenario is; C: 140400
How to solve propbability Combinations?
There are 26 alphabets in english. Now, if there are no repetitions, then;
Number of ways of selecting first letter = 26
Number of ways of selecting second letter = 25
Number of ways of selecting third letter = 24
Thus;
Number of ways of selecting three letters from the alphabet if there is no repetition is; P(3 letters) = 26 * 25 * 24 = 15600
Number of ways of selecting 1 out of the 9 numbers is = 9
Thus;
Potential passwords that can be created = 15600 * 9 = 140400
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