Answer :
Answer:
[tex]8.42\ \text{mL}[/tex]
Explanation:
When the endpoint is reached the millimoles of sodium acetate and HCl will be equal.
[tex]\text{Volume of sodium acetate}=25\ \text{mL}[/tex]
[tex]\text{Molarity of sodium acetate}=0.033M[/tex]
[tex]\text{Molarity of HCl}=0.098M[/tex]
[tex]\text{Millimoles of sodium acetate}=25\times 0.033=0.825\ \text{mmol}[/tex]
Let [tex]V=\text{Volume of HCl}[/tex]
[tex]\text{Millimoles of HCl}=0.098V[/tex]
At end point the millimoles will be equal to that of sodium acetate
[tex]0.825=0.098V\\\Rightarrow V=\dfrac{0.825}{0.098}\\\Rightarrow V=8.42\ \text{mL}[/tex]
The volume of HCl required is [tex]8.42\ \text{mL}[/tex].
The volume of HCl required to required to reach endpoint is 8.42 mL
From the question,
We are to determine the volume of HCl required to reach endpoint
First, we will write a balanced chemical equation for the reaction.
The balanced chemical equation for the reaction is
CH₃COONa + HCl → CH₃COOH + NaCl
This means
1 mole of sodium acetate is required to completely neutralize 1 mole of HCl
Now, we will determine the number of moles of sodium acetate present
Using the formula
Number of moles = Concentration × Volume
Concentration of sodium acetate = 0.033 M
Volume of sodium acetate = 25.00 mL = 0.025 L
∴ Number of moles of sodium acetate present = 0.033 × 0.025
Number of moles of sodium acetate present = 0.000825 mole
Now,
Since, 1 mole of sodium acetate is required to completely neutralize 1 mole of HCl
Then,
0.000825 mole of sodium acetate would be required to completely neutralize 0.000825 mole of HCl
∴ The number of moles of HCl needed is 0.000825 mole
Now, for the volume of 0.098 M HCl required to reach endpoint
Using the formula
[tex]Volume = \frac{Number\ of\ moles}{Concentration}[/tex]
∴ Volume of HCl required to required to reach endpoint = [tex]\frac{0.000825}{0.098}[/tex]
Volume of HCl required to required to reach endpoint = 0.008418367 L
Volume of HCl required to required to reach endpoint = 8.418367 mL
Volume of HCl required to required to reach endpoint ≅ 8.42 mL
Hence, the volume of HCl required to required to reach endpoint is 8.42 mL
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