Answer :
perpendicular to y=something is x=something
just look at the x coordinate of the point
(x,y)
(2,6)
the line is x=2
just look at the x coordinate of the point
(x,y)
(2,6)
the line is x=2
The required equation of line will be 3y = x + 16.
It is given that a line perpendicular to y= - 3 passes through coordinate (2,6).
We have to find out the equation of the line.
What is the general equation of a line ?
The equation of a line is y = mx + c.
Given,
y=-3
After comparing with the general equation of a line y = mx + c. We found that value of slope m = -3.
Slope of perpendicular line m1 = -1/m = 1/3
Equation of perpendicular line passing through (x1,y1)=(2,6) is ,
(y-y1) = m (x-x1)
(y-6) = (1/3) (x-2)
3y - 18 = x-2
3y = x + 16
Thus, the equation of the line will 3y=x+16.
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