A local library shows movies on Thursday evenings. The library administrator has chosen the next six movies he will show, but he has not decided in which order to show them. How many possible offerings of the six movies are there
There are 6 choices for the first movie. Having chosen the first movie there are 5 choices for the second, 4 choices for the third, 3 for the fourth, 2 for the fifth and 1 for the last. Therefore the number of possible offerings is: [tex]6\times5\times4\times3\times2\times1=720[/tex] The answer is 720.
