Answered

A 2.00 kg ball is thrown upward at some unknown angle from
the top of a 20.0 m high building. If the initial magnitude of the
velocity of the ball is 20.0 m/s. What is the value of total
energy?

Answer :

Answer: 792J

Explanation:

Cricetus

The value of the total energy will be "792 Joules". To undestand the calculation, check below.

Energy and Velocity

According to the question,

Mass of ball, m = 2.0 kg

Building's height, h = 20.0 m

Ball's initial velocity, v = 20.0 m/s

We know the formula,

Potential energy (U) = mgh

Kinetic energy (K) = [tex]\frac{1}{2}[/tex] mv²

and,

The total energy be:

= U + K

= mgh + [tex]\frac{1}{2}[/tex] mv²

By substituting the values,

= 2.00 × 9.8 × 20.0 + [tex]\frac{1}{2}[/tex] × 2.00 × (20.0)²

= 392 + 400

= 792 Joules

Thus the above answer is correct.

Find out more information about energy here:

https://brainly.com/question/20562687

Other Questions