Answer :
Answer:
b) farther
Explanation:
The range of the bullet shot horizontally just above the horizontal ground is given as;
[tex]R_1 = \frac{u^2sin(2\theta)}{g}[/tex]
where;
θ is the angle of projection with the horizontal ground = 0
R₁ = 0
The range of the bullet shot at an angle of 30 degrees with the same initial velocity as the first bullet is given as;
[tex]R_2 = \frac{u^2sin(2 \theta)}{g} \\\\R_2 = \frac{u^2sin(2*30)}{9.8}\\\\R_2 = 0.088u^2[/tex]
Therefore, the second bullet will travel a horizontal distance that is farther