Answer :
a )
P ( x = 3 ) = 5/90 * 4/89 * 3/88 = 1 / 11,748 = 0.000085
b )
Probability of selecting zero defective cartridges:
P ( x = 0 ) = 85/90 * 84/89 * 83/88 = 592,620 / 704,880 = 0.840739
P ( at least 1 defective) = 1 - 0.840739 = 0.159261
P ( x = 3 ) = 5/90 * 4/89 * 3/88 = 1 / 11,748 = 0.000085
b )
Probability of selecting zero defective cartridges:
P ( x = 0 ) = 85/90 * 84/89 * 83/88 = 592,620 / 704,880 = 0.840739
P ( at least 1 defective) = 1 - 0.840739 = 0.159261