Answer :
We have to find what consecutive integers does the square root of 115 lie.
100 < 115 < 121
10² < 115 < 11²
√115 ≈ 10.7238
Answer:
The square root of 115 lies between C ) 10 and 11
100 < 115 < 121
10² < 115 < 11²
√115 ≈ 10.7238
Answer:
The square root of 115 lies between C ) 10 and 11