Answer :
Answer:
20ft by 40ft
Step-by-step explanation:
The area of the fence is 800 ft². Let x represent one side of the fence and y the other side of the fence, hence:
xy = 800 (1)
The cost of fencing (C) is:
C = 3x + x + y + y
C = 4x + 2y (2)
From xy = 800, y = 800/x. Substituting in equation 2:
[tex]C = 4x +2( \frac{800}{x})\\\\Minimum \ cost\ is\ at\ C'=0\\\\Hence:\\ \\C'=4-\frac{1600}{x^2} \\\\4-\frac{1600}{x^2} =0\\\\4=\frac{1600}{x^2} \\\\x=\sqrt{\frac{1600}{4} } \\\\x=20\ ft\\\\y=\frac{800}{x} =\frac{800}{20}=40\ ft[/tex]