Answer:
[tex]\frac{x+9}{x+3}[/tex] , x ≠ - 3 ;
Step-by-step explanation:
f(x) = x³ + 9x² - 25x - 225 = (x + 9)(x + 5)(x - 5)
g(x) = x³ + 3x² - 25x - 75 = (x + 5)(x + 3)(x - 5)
( [tex]\frac{f}{g}[/tex] )(x) = [tex]\frac{(x+9)(x+5)(x-5)}{(x +5)(x+3)(x-5)}[/tex] = [tex]\frac{x+9}{x+3}[/tex] , x ≠ - 3
