find the value of x

Answer:
Step-by-step explanation:
RQ < PR < PQ
TV < UV < UT
ΔPQR~ΔUTV ⇒ [tex]\dfrac{RQ}{TV}=\dfrac{PR}{UV}[/tex]
[tex]\dfrac{8}{x-3}=\dfrac{14}{x+6}\\\\8(x+6)=14(x-3)\\\\8x+48=14x-42\\\\48+42=14x-8x\\\\90=6x\\\\x=90:6=15[/tex]