Answer :
Answer:
The cup would contain 10.16 ounces.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean of 10 ounces, standard deviation of 1 ounce:
This means that [tex]\mu = 10, \sigma = 1[/tex]
If we simulated the filling process, and had the random number .564, how many ounces would the cup contain?
This means that we have to find X when Z has a pvalue of 0.564. So X when Z = 0.16. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.16 = \frac{X - 10}{1}[/tex]
[tex]X - 10 = 0.16*1[/tex]
[tex]X = 10.16[/tex]
The cup would contain 10.16 ounces.