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A parabola has a vertex at (3, 1) and goes through the point (2, -1). Explain how you would write the equation of the parabola given this information. Then describe the domain and range. Additionally, discuss whether the function has a maximum or minimum, how you know this, and identify the value.

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Answer:

The parabola has the following characteristics:

(i) [tex]Dom\{f(x)\} = \mathbb{R}[/tex]

(ii) [tex]Ran\{f(x)\} = (-\infty, 1][/tex]

(iii) The parabola has an absolute maximum since [tex]C < 0[/tex].

(iv) The vertex parameter of the parabola is -2.

Step-by-step explanation:

Let suppose that parabola has a vertical axis of symmetry. From Analytical Geometry, the vertex form of the equation of the parabola is defined by the following formula:

[tex]y-k = C\cdot (x-h)^{2}[/tex] (1)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]h[/tex], [tex]k[/tex] - Coordinates of the vertex.

[tex]C[/tex] - Vertex parameter.

If we know that [tex](x,y) = (2,-1)[/tex] and [tex](h,k) = (3,1)[/tex], then the vertex parameter of the parabola is:

[tex]-1-1 = C\cdot (2-3)^{2}[/tex]

[tex]-2 = C[/tex]

[tex]C = -2[/tex]

According to this information, we find the following characteristics:

(i) [tex]Dom\{f(x)\} = \mathbb{R}[/tex]

(ii) [tex]Ran\{f(x)\} = (-\infty, 1][/tex]

(iii) The parabola has an absolute maximum since [tex]C < 0[/tex].

(iv) The vertex parameter of the parabola is -2.

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