Answer :
Answer:
zeros of F(x) are 1, 3 + [tex]\sqrt{13}[/tex], -3 + [tex]\sqrt{13}[/tex]
Step-by-step explanation:
You need to solve the equation F(x) = 0
[tex]x^{3} - 7x^{2} + 2x +40 = (x - 1)(x^{2} - 6x - 4) = 0\\ x = 1 \\ or \\ x^{2} - 6x -4 = 0[/tex]
Now solve the quadratic equation above using the quadratic formula.
You should get
[tex]3 + \sqrt{13} \\ -3 + \sqrt{13}[/tex]
So, the zeros of F(x) are 1, 3 + [tex]\sqrt{13}[/tex], -3 + [tex]\sqrt{13}[/tex]