The correct answer to the question is [tex]336.98\times 10^4\ J[/tex]
CALCULATION:
The acceleration of the truck is given as a = [tex]0.0083\ m/s^2[/tex]
The mass of truck is given as m = 7000 kg.
The distance travelled by the truck S = [tex]5.8\times 10^{4}\ m[/tex].
The force applied on the truck is calculated as -
Force F = mass × acceleration
= [tex]7000\ kg\times 0.0083\ m/s^2[/tex]
= 58.1 N.
We are asked to calculate the work done .
The work done by a body is calculated as -
W = [tex]\vec F.\vec S[/tex]
= [tex]FScos\theta[/tex]
Here, [tex]\theta[/tex] is the angle between force and displacement.
If [tex]\theta=0^{0}[/tex], then W = FS
Hence, the work done by the truck W = FS
= [tex]58.1\ N\times 5.8\times 10^{4}\ m[/tex]
= [tex]336.98\times 10^4\ J[/tex]
Here, J ( joule ) is the unit of work.
