Answer :
Answer:
E = 216.76 J
Explanation:
The amount of energy absorbed by the goalkeeper will be equal to the difference between the initial and the final kinetic energy of the ball.
[tex]Energy\ Absorbed = Initial\ Kinetic\ Energy - Final\ Kinetic\ Energy\\Energy\ Absorbed = E = \frac{1}{2}mv_{i}^2 - \frac{1}{2}mv_{f}^2\\E = \frac{1}{2}m(v_{i}^2 - v_{f}^2)\\[/tex]
where,
m = mass of ball = (16 ounce)(0.0283495 kg/1 ounce) = 0.4535 kg
vf = final velocity = 2.25 m/s
vi = initial velocity = 31 m/s
Therefore,
[tex]E = \frac{1}{2}(0.4535\ kg)[(31\ m/s)^2 - (2.25\ m/s)^2][/tex]
E = 216.76 J