Answer :
The sum of the 48 terms will be $2,496. Then the correct option is A.
What is the arithmetic sum of sequence?
Let a₁ be the first term, n the number of the terms, and l be the last term of the sequence.
Then the sum of all the terms will be given as,
S = [n (a₁ + l )] / 2
Let a₁ be the first term and d is the common difference between the terms. Then the nth term will be given as
[tex]\rm a_n = a_1 + (n - 1)d[/tex]
Beginning with Rodney’s first month of high school, his father deposits $5 into Rodney’s savings account.
Each month after the first month, his father deposits $2 more than the previous month.
Then the first term is $5 and the common difference is $2.
The total amount deposited in Rodney’s account after four years can be represented using the expression.
Then the total number of the terms will be
n = 4 x 12
n = 48 months
Then the 48th term of the sequence will be
a₄₈ = 5 + (48 – 1) · 2
a₄₈ = 5 + 47 · 2
a₄₈ = 5 + 94
a₄₈ = 99
Then the sum of the 48 terms will be
S = 48 (5 + 99) / 2
S = 24 × 104
S = $2,496
Then the correct option is A.
More about the arithmetic sum of sequence link is given below.
https://brainly.com/question/14021449
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