Katarinche
Answered

2sinxcosx-sin(2x)cos(2x)=0

A. give the most general solutions to equation
B. simplify the first expression using double angle identity for sine
C. factor the left side of equatioin
D. solve the factored equation

Answer :

syed514
 2sinxcosx = sin(2x)
2sinxcosx-sin(2x)cos(2x)=0
sin(2x)-sin(2x)cos(2x)=0

now factor out sin(2x)
sin(2x)[1 - cos(2x)] = 0
sin(2x) = 0
since
sin(0) = 0
2x = 0
x = 0

Other Questions