Answer :
2sinxcosx = sin(2x)
2sinxcosx-sin(2x)cos(2x)=0
sin(2x)-sin(2x)cos(2x)=0
now factor out sin(2x)
sin(2x)[1 - cos(2x)] = 0
sin(2x) = 0
since
sin(0) = 0
2x = 0
x = 0
2sinxcosx-sin(2x)cos(2x)=0
sin(2x)-sin(2x)cos(2x)=0
now factor out sin(2x)
sin(2x)[1 - cos(2x)] = 0
sin(2x) = 0
since
sin(0) = 0
2x = 0
x = 0