Given:
A line passes through the points (-3,3) and (0,-1).
To find:
The slope intercept form of the line.
Solution:
The slope intercept form of a line is:
[tex]y=mx+b[/tex] ...(i)
Where, m is the slope and b is the y-intercept.
A line passes through the points (-3,3) and (0,-1). So, the slope of the line is:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\dfrac{-1-3}{0-(-3)}[/tex]
[tex]m=\dfrac{-4}{3}[/tex]
The line intersect the y-axis at point (0,-1). So, the y-intercept is -1.
Putting [tex]m=\dfrac{-4}{3},b=-1[/tex] in (i), we get
[tex]y=-\dfrac{4}{3}x+(-1)[/tex]
[tex]y=-\dfrac{4}{3}x-1[/tex]
Therefore, the slope intercept form of the line is [tex]y=-\dfrac{4}{3}x-1[/tex].
