Answered

A sample of nitrogen gas occupies a volume of 2.00 L at 756
mm Hg and 0.00°C. The volume increases by 2.00 L and the
temperature decreases to 137 K What is the final pressure
exerted on the gas?

Answer :

jvee40

Answer:

Pf= 190 mmHg

Explanation:

(Pi×Vi)/Ti = (Pf×Vf)/T2

Initial Pressure Pi = 756mmHg,

Initial Volume Vi = 2L,

Initial Temperature Ti = 0°C=273K

Final Pressure Pf = ?,

Final Volume Vf = 2L+ Vi = 4L,

Final Temperature T2= 137K

Pf = (Pi × Vi × T2 )/(Vf × Ti)

Pf = (756 × 2 × 137)/(4 × 273)

Pf = 189.7 mmHg

Pf approx. 190mmHg

The combined gas law states the relationship between temperature, pressure, and volume. The final pressure of the gas is 190 mmHg.

What is combined gas law?

Combined gas law states the relationship between the initial pressure, volume, and temperature to the final and is given as,

[tex]\rm \dfrac{P_{i} \times V_{i}}{T_{i}} = \rm \dfrac{P_{f} \times V_{f}}{T_{f}}[/tex]

Given,

Initial Pressure = 756 mmHg

Initial Volume = 2 L

Initial Temperature = 273 K

Final Volume = 4 L

Final Temperature = 137 K

The final pressure is calculated as:

[tex]\begin{aligned} \rm P_{f} &= \rm \dfrac{P_{i} \times V_{i} \times T_{f}}{V_{f} \times T_{i}}\\\\&= \dfrac{756 \times 2 \times 137}{4 \times 273}\\\\&= 189.7 \;\rm mmHg\end{aligned}[/tex]

Therefore, 190 mmHg is the final pressure.

Learn more about combined gas law here:

https://brainly.com/question/14910542

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