Hi, i need to calculate roots x1 and x2 using the vieta theorem, can anyone help me? I have found the answer for x1 and x2, its 1,5 and 2, all i need is a solution on how to get this answer, the equation is in the picture, will give you brainliest if you type down the correct solution for me, thanks.

Hi, i need to calculate roots x1 and x2 using the vieta theorem, can anyone help me? I have found the answer for x1 and x2, its 1,5 and 2, all i need is a solut class=

Answer :

msm555

Answer:

Solution given:

-2x²+7x-6=0

2x²-7x+6=0

Comparing above equation with ax²+bx+c

we get

a=2

b=-7

c=6

By using Vieta's theorem

X1+X2=[tex] \frac{-b}{a} [/tex]=[tex] \frac{7}{2} [/tex]

again

X1X2=[tex] \frac{c}{a} [/tex]=[tex] \frac{6}{2} [/tex]=3

  • -2x²+7x-6=0
  • 2x²-7x+6=0
  • 2x²-4x-3x+6=0
  • 2x(x-2)-3(x-2)=0
  • (2x-3)(x-2)=0
  • x=3/2 or 2

x1x2=3

x1+x2=7/2

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