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1. A diode laser has a band gap of eV0, where V0 is a voltage. The laser has an efficiency of 30%, meaning 30% of the power input is converted to laser light output. We run an electrical current I through the diode, where I is in amps.a. What is the wavelength of the photons produced by the laser

Answer :

Answer:

Hence wavelength of the photons produced by the laser is

[tex]\frac{hc}{eV_0}[/tex]

Explanation:

Given

Efficiency of laser - 30%

As we know

[tex]eV_0 = \frac{hc}{\Lambda}[/tex]

h = plank's constant

c = speed of light

eV0 = band gap

Hence wavelength of the photons produced by the laser is

[tex]\Lambda= \frac{hc}{eV_0}[/tex]

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