agsmith0216
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Which is the equation of a parabola with vertex (0, 0), that opens to the left and
has a focal width of 12?
a. y2 = 12x
b. y2 = -12x
c.x = 12y
d. x = -12y

Answer :

Answer:

Step-by-step explanation:

I'm going to guess that the square  exponents are on the top y's   only?   then answer b) looks good

Answer:

b. y^2 = -12x

Step-by-step explanation:

The general form for  the given parabola is y^2 = -4ax where the focus is at (-a, 0). The focal width is 4a which in this case = 12.

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