Answer :
Answer:
Solution given:
(x1,y1)=(-3,2)
(x2,y2)=(2,2)
length[d]=?
we have
d=[tex] \sqrt{(x2-x1)²+(y2-y1)²} [/tex]
=[tex] \sqrt{(2+3)²+(2-2)²} [/tex]
=[tex] \sqrt{5²} [/tex]
=5units
D 5 units is a right answer.
Answer:
Solution given:
(x1,y1)=(-3,2)
(x2,y2)=(2,2)
length[d]=?
we have
d=[tex] \sqrt{(x2-x1)²+(y2-y1)²} [/tex]
=[tex] \sqrt{(2+3)²+(2-2)²} [/tex]
=[tex] \sqrt{5²} [/tex]
=5units
D 5 units is a right answer.