Solve for the value of x

Answer:
X=5
Step-by-step explanation:
[tex]{x}^{2} + {(2x + 2)}^{2} = {(2x + 3)}^{2} \\ {x}^{2} + 4 {x}^{2} + 8x + 4 = 4 {x}^{2} + 12x + 9 \\ 5 {x}^{2} + 8x + 4 = 4 {x}^{2} + 12x + 9 \\ {x}^{2} - 4x - 5 = 0 \\ x = - 5 \: or \: x = 5 \\ x = 5[/tex]