A parallelogram has the vertices T(-4,2), (2,4), V(3,1), and W(-3,-1).
1. Determine the lengths of each side using the distance formula.
1. Determine if the slopes of two consecutive sides are parallel,
perpendicular or neither.
1. What type of parallelogram is created with the given points?
Explain your answer.
Brainlist so who ever gives the right answer

Answer :

sreedevi102

Answer:

T= (-4 ,2)

U= (2 ,4)

V= (3 ,1)

W= (-3, -1)

1 . LENGTH OF EACH SIDES

 [tex]length \ of \ sides =\sqrt{(x_{2} -x_{1} )^2+(y_{2} -y_{1})^2}[/tex]

[tex]length \ of \ TU = \sqrt{(2--4 )^2+(4-2)^2} = \sqrt{40}[/tex]

[tex]Length \ of \ UV =\sqrt{(3-2 )^2+(1-4)^2} = \sqrt{10}[/tex]

[tex]Length \ of \ VW =\sqrt{(-3-3)^2+(-1-1)^2} = \sqrt{40}[/tex]

[tex]length \ of \ TW =\sqrt{(-3--4 )^2+(-1-2)^2} =\sqrt{10}[/tex]

2. SLOPE OF CONSECUTIVE SIDES

[tex]Slope \ of \ the \ line \ passing \ through \ (x_{1}, y_{1} ) \ and \ (x_{2}, y_{2}) = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

[tex]Slope \ of \ TU = \frac{4-2}{2--4} = \frac{2}{6} =\frac{1}{3}[/tex]

[tex]Slope \ of \ UV = \frac{1-4}{3-2} = -3[/tex]

[tex]Slope \ of \ VW = \frac{-1-1}{-3-3} = \frac{-2}{-6} =\frac{1}{3}[/tex]

[tex]Slope \ of \ TW = \frac{-1-2}{-3--4} = -3[/tex]

[tex]Slope \ of \ lines \ parallel \ to \ each \ other = m_{1}\cdot m_{2} = 1\\Slope\ of \ lines\ perpendicular \ to \ each \ other =m_{1}\cdot m_{2} = -1\\[/tex]

[tex]Slope \ of \ TU * UV = \frac{1}{3}*-3 = -1\\\\Slope \ of \ UV *VW = -3 *\frac{1}{3}= -1\\\\ Slope \ of \ VW * TW = \frac{1}{3}*-3 = -1\\\\Slope \ of \ TW * TU = -3 *\frac{1}{3}= -1\\\\[/tex]

Therefore the consecutive sides are perpendicular to each other.

3. TYPE OF PARALLELOGRAM

The opposite sides are of same length.  The consecutive sides are perpendicular to each other. So the parallelogram is a RECTANGLE.

Other Questions