Hagrid
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"An air traffic controller observes two airplanes approaching the airport. The displacement from the control tower to plane 1 is given by the vector A⃗ , which has a magnitude of 220 km and points in a direction 32 ∘ north of west. The displacement from the control tower to plane 2 is given by the vector B⃗ , which has a magnitude of 140 km and points 65 ∘ east of north.

Sketch the vectors A⃗ , B⃗ , and D⃗ =A⃗ −B⃗ . Notice that D⃗ is the displacement from plane 2 to plane 1. Draw the vectors with their tails at the dot. The orientation of your vectors will be graded. The exact length of you"

Answer :

The solution to the problem is as follows:

Ax= (-220km)cos32
 
Ay= (220km)sin32

Bx= (140km)cos65
 
By=(140km)sin65

Careful: The angle here is given with respect to the North (y), not the East (x).

You can find the magnitude and direction of vector C by basing on my solution!

I hope my guide has come to your help. Have a nice day ahead and may God bless you always!

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