Step-by-step explanation:
By question , it's given that the X intercept is (5,0) and the y intercept is (0,8) . And we need to find the y-intercept of the graph of f(x) + 3 . For that , firstly let's find out the equation of the line.
[tex]\sf\implies y- y_1 = \bigg(\dfrac{y_2-y_1}{x_2-x_1}\bigg) ( x - x_1) \\\\\sf\implies y - 0 = \bigg(\dfrac{0-8}{5-0}\bigg)( x - 5 ) \\\\\sf\implies y = \dfrac{-8}{5}( x - 5 ) \\\\\sf\implies 5y = -8x +40 \\\\\sf\implies 8x + 5y - 40 = 0 [/tex]
Let us say that this is f(x) :-
[tex]\\\\\sf\implies f(x) = 8x + 5y - 40 \\\\\sf\implies \boxed{\sf\red{ f(x)+3 = 8x +5y -37 }}[/tex]
Plot its graph :-
We can either convert it into intercept form but plotting a graph can also be done to find y intercept .
[tex]\implies \boxed{\pink{\sf y - intercept = 7.4}}[/tex]
Refer to attachment for graph .
Hence the y Intercept is 7.4 .
