Use distributive law
[tex]\boxed{\sf a(b+c)=ab+ac}[/tex]
Now
[tex]\\ \sf\longmapsto 2x(x-y)+3y(x-y)[/tex]
[tex]\\ \sf\longmapsto 2x^2-2xy+3xy-3y^2[/tex]
[tex]\\ \sf\longmapsto 2x^2-3y^2-2xy+3x^2[/tex]
[tex]\\ \sf\longmapsto 2x^2-3y^2+xy[/tex]
Taking common
Answer: 2x (x-y) + 3y (x-y)
= ( x-y ) ( 2x-3y )
