Answer :
This situation is represented by the following disjoint inequality:
[tex]m > -\frac{23}{3} \cup m \leq -10[/tex]
---------------------------
- The format of a disjoint inequality is:
[tex]x > a \cup x \leq b[/tex]
- Which is read as: x is more than a or at most b.
---------------------------
- In this question, we have number m more than [tex]-7\frac{2}{3} = -7 - \frac{2}{3} = -\frac{21}{3} - \frac{2}{3} = -\frac{23}{3}[/tex] and at most -10, thus, the disjoint inequality that represents this situation is:
[tex]m > -\frac{23}{3} \cup m \leq -10[/tex]
A similar problem is given at https://brainly.com/question/24528399