The resulting coordinate of the pre-image will be at A"(-4, -8), B"(10, -3) and C"(0,7)
Given the coordinate of the triangle ΔABC as A (-4,-6), B (3,-6), and C (-2,-1).
If the coordinate is dilated by a factor of 2, this means we will multiply each of the coordinate point by 2 as to have:
A' = (2(-4), 2(-6)) = (-8, -12)
B' = (2(3), 2(-6)) = (6, -12)
C' = (2(-2), 2(-1)) = (-4, -2)
If the coordinate has a centre of dilation of (-4, -9), the final position of the image will be at;
A" = (-8+4, -12+4) = (-4, -8)
B" = (6+4, -12+9) = (10, -3)
C" = (-4+4, -2+9) = (0, 7)
Hence the resulting coordinate of the pre-image will be at A"(-4, -8), B"(10, -3) and C"(0,7)
Learn more on dilation here: https://brainly.com/question/3189516
