3) y = [tex]-\frac{1}{2}[/tex]x + 3
Slope-intercept form is y = mx + b when m is the slope and b is the y-intercept
b = 2 (line hits y-axis at 2)
m = [tex]\frac{rise}{run} or\frac{change.in.y}{change.in.x}[/tex] so [tex]\frac{1}{2}[/tex] and the line is negative, so [tex]-\frac{1}{2}[/tex]
Write our equation by putting the parts together, and we get:
y = [tex]-\frac{1}{2}[/tex]x + 3
4) y = [tex]-\frac{2}{3}[/tex]x - 1.67
Point slope form is y - y1 = m (x - x1) when y1 is the y coordinate of the point, m is the slope, and x1 is the x coordinate of the point
y - y1 = m (x - x1)
Finding the slope (same as above) results in [tex]-\frac{2}{3}[/tex]
*aaaa I have to go, good luck, I do have the answer just no times to write out the steps, good luck and have a nice day!*
