Answer :
Replace all occurrences of x with y + 3 in each equation.
Replace all occurences of x in 6x - 5y = 15 with y + 3.
6 (y+3) -5y = 15
x = y + 3
Simplify 6 (y + 3) - 5y.
Simplify each term.
Apply the distributive property.
6y + 6 · 3 - 5y = 15
x = y + 3
Multiply 6 by 3.
6y + 18 - 5y = 15
x = y + 3
Subtract 5y from 6y.
y + 18 = 15
x = y + 3
Move all terms not containing y to the right side of the equation.
Subtract 18 from both sides of the equation.
y = 15 - 18
x = y + 3
Subtract 18 from 15.
y = -3
x = y + 3
Replace all occurences with y with -3 in each equation.
Replace all occurences of y in x = y + 3 with -3.
x = (-3) + 3
y = -3
Add -3 and 3.
x = 0
y = -3
The solution to the system is the complete set of ordered pairs that are valid solutions.
(0,-3)
The result can be shown in multiple forms.
Point Form:
(0,-3)
Equation Form:
x = 0, y = -3
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The required values are :
- [tex]x = 0[/tex]
- [tex]y = - 3[/tex]
Refer to the attachment for solution ~
